Call Us : + 9810236711, 011-69000403

Startiges

Startiges

Strategy for Chemistry Optional:-
Civil services examination these days have become one of toughest examination, looking at the level of competition involved in this examination one can qualify this through  proper planning & management simply hard-work  cannot  guarantee your success in this exam. First step in the proper planning is right selection of optional. In my opinion optional subject should be chosen on the basis of one’s interest, scoring pattern, availability of study material, & expert guidance.

Secret of Scoring Maximum marks:-
A detail analysis of chemistry syllabus and pattern of recent year questions reveals that chemistry is a one of scoring subject in CSE-mains examination with minimum effort: focused approach, selection of books with understanding & Proper guidance is key for the scoring 280 plus marks.

How to prepare for mains Exam:-
Over all chemistry syllabus is divided in two papers. First paper includes physical. Chemistry & Part of Inorganic chemistry while second paper include organic chemistry and spectroscopy.

First paper is mathematical as well as theoretical. For physical chemistry part one required good understanding & proper presentation ability to secure good marks. Minimum efforts for preparation of this paper can be achieved by dividing this subject in to three parts.

  1. Static physical chemistry:- Liquid state, Gaseous state, Thermodynamics & Phase equilibria.
  2. Dynamic Physical chemistry:- Electrochemistry, Chemical kinetics,Surface Chemistry and Photochemistry
  3. Structural physical chemistry:– Atomic structure, Chemical bonding & Solid state.  To minimize the effort of preparation students must study these topic together Because they are interlinked topic. To explain this thermodynamic includes properties of gases and phase equilibriums is an  application of thermodynamics if sequence of study in broken then students must require more time as compared to sequential study. An overall question from physical chemistry includes mathematical derivation, numericals (now a day a percentage increasing) and also theoretical principle of physical chemistry. Remember your answer must be concise, comprehensive, and clear in my language triple C(CCC) is key of  success for good score in this section. All the assumptions, proper figure/ diagram, through analysis, along with practical application must be included in your answer. To explain this I take one example. Like –“Discuss the principle of polarograpy, your answer must include.
  • It is application of irreversible electrochemistry.
  • II – Different Type of polarizations.  
  • III –Explain concentration polarization.
  • IV – Give proper diagram
  • V- Derive the mathematical relation between.
  • Diffusion current & E1/2
  • Such a clear representation can provide you 80% marks. Second part of this paper is Inorganic chemistry which contribute 1/3rd weightage. Inorganic chemistry is chemistry of facts, theoretical principle and structural identification. First step in preparation of this is selection of good books followed by preparation of comprehensive notes, writing ability with sequential representation of facts is key of scoring good marks in this section.

    Paper II –
    Paper II is organic chemistry with spectroscopy for the purpose of preparation this paper can be divided in three sections.
  • General organic Chemistry:- Aromaticity, Reaction Mechanism including Pericyclic reaction.
  • Synthetic organic chemistry:- Named reaction, Photochemistry, Reagent & polymer.
  • Spectroscopy
  • For minimum effort to expertise this paper one must follow this sequence because  basic of general organic chemistry become facts of synthetics  organic chemistry. To elaborate this, reaction mechanism is completely applied to study any named reaction or any application of reagent. A good command on reaction mechanism minimizes your time in study of named reaction & synthetic reagent. Organic Chemistry is more scoring as compared to any other branch of chemistry overall organic chemistry depends upon three words of English i.e. WHAT, HOW & WHY a student must prepare this paper  accordingly, to elaborate this, take example discuss product (s) of this reaction.


    In this question we have to identify these two products now. If one is major the other is minor it must be stated very clearly & suppose A is major product then  why it is major product it must be explained clearly.
    Now dear students whenever your approach any Organic question reduce this on these three word and answer accordingly this approach will provide you to manage time in this paper and also provide a precise and concise answer. 

    Spectroscopy
    It is another branch of this paper having nearly 1/3rd weightage 150 plus score in this paper depend upon score in this section. This section is completely analytical in which students have to memorize several spectroscopy data. My first advise in go through more than one book and make a comprehensive notes along with computation of data. Then starts practicing the problem. Concise & compact answer with analysis of each & every spectroscopy data given in questions  is only key of achieving good marks in this paper. To elaborate this  I am giving a model solution. 

    Question.
    Treatment of this keto–aldhyde with KOH gives a compound C7H10O with spectroscopic data is given, what is its structure and how it formed? Assign NMR data and give mechanism.

    Answer.
    Whenever two carbonyl is separated by at least two carbon atoms it undergoes intra molecular Aldol condensation leading to cyclisation.


    Paper – I
    Course Detail

    Atomic Structure - 08 Hours
    Chemical Bonding 13 Hours
    Solid State 08 Hours
    Liquid State 03 Hours
    Gaseous State  – 04 Hours
    Thermodynamics 14 Hours
    Phase Equilibrium   – 06 Hours
    Electrochemistry 12 Hours
    Chemical Kinetics 08 Hours
    Surface Chemistry   – 03 Hours
    Photochemistry   – 03 Hours
    f-block   – 0.3 Hours
    Coordination Compounds   – 12 Hours
    P –block Chemistry   – 03 Hours
    Total Hours - 100 hr

    • Phase Test 1         –         Atomic Structure + Chemical Bonding + Solid State
    • Phase Test 2         –         Liquid State + Gaseous State + Thermodynamics
    • Phase Test 3         –         Phase Equilibrium + Electrochemistry + Chemical Kinetics
    • Phase Test 4         –          Surface Chemistry + Photochemistry + f-block
    • Phase Test 5         –         Coordination Compounds + P –block Chemistry



    Paper – II
    Course Detail

    Aromaticity 05 Hours
    Reactions Mechanism 45 Hours
    Rearrangements 05 Hours
    Named Reaction 10 Hours
    Pericyclic Reaction 06 Hours
    Photochemistry 06 Hours
    Reagents 05 Hours>
    Spectroscopy 14 Hours
    Polymers 04 Hours
    Total Hours 100 hr


    • Phase Test 1   –          Aromaticity + Reactions Mechanism
    • Phase Test 2   –         Reactions Mechanism
    • Phase Test 3   –          Named Reaction + Reagents  
    • Phase Test 4   –          Pericyclic Reaction + Photochemistry
    • Phase Test 5 –            Spectroscopy  + Polymers